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I have a shell script that runs every night to backup my EC2 sites database and html to S3, and when it backs the folders up, it appends the date to it for easier viewing. But I want it to also be able to delete the relevant backup folders from 3 days before. How
2011年1月21日 · DateTime x = YourDateBasis; y = x.AddMonths(6); y = x.AddMonths(3); y = x.AddMonths(2); Then to edit from comment, Date Math per the period cycle of the person's account, you would simply need the start and end date and keep adding respective months until you've created all expected months.
2011年10月14日 · Stack Overflow for Teams Where developers & technologists share private knowledge with coworkers This is so the right answer. Eg: to get difference in days do Math.floor((date2 - date1) / (1000*60*60*24))-- for difference in any other unit, adjust the denominator (the base value is in ms).
2014年10月6日 · For date-time management and processing I warmly suggest you existing libraries. Leverege on them to execute this kind of calculation. I usually work with moment.js .
2022年3月11日 · from datetime import date def calculate_age(born): today = date.today() try: birthday = born.replace(year=today.year) except ValueError: # raised when birth date is February 29 and the current year is not a leap year birthday = born.replace(year=today.year, month=born.month+1, day=1) if birthday > today: return today.year - born.year - 1 else: return today.year - born.year
I want a Java program that calculates days between two dates. Type the first date (German notation; with whitespaces: "dd mm yyyy") Type the second date. The program should calculates the number o...
2008年9月29日 · There seems to be a problem with your code. If you try daysBetweenDates(*(2013,2,28,2013,1,1,False)), it will end up in an infinite loop because the condition y1 > y2 in the daysBetweenDates is not very well thought-out.
2013年2月7日 · So what I want to do is create a function that can take in input date, calculate X number of days/weeks/months later (or before) and output the resulting date. The trick being to remember to calculate leap years, months that have more or less than 30 days, etc. I'm pretty new to Visual Basic so I don't really know where to start with this.
Adjusted to allow for daylight saving differences. try this: function daysBetween(date1, date2) { // adjust diff for for daylight savings var hoursToAdjust = Math.abs(date1.getTimezoneOffset() /60) - Math.abs(date2.getTimezoneOffset() /60); // apply the tz offset date2.addHours(hoursToAdjust); // The number of milliseconds in one day var ONE_DAY = 1000 * 60 * 60 * 24 // Convert both dates to ...
You say: printf("%d ,%d, %d, is a %d", year,month,day,total_num); That's going to print. L, M, N, is a P. where L, M, N, and P are numbers. You need that printf() before the name-of-days switch and need to remove the final %d and the total_num from the printf. Then that printf will print.
